What is expand 2pi-pi/2 (-1/2 ln(7)+3) ?

The solution to expand 2pi-pi/2 (-1/2 ln(7)+3) is 2pi+pi/4 ln(7)-(3pi)/2

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expand 2pi-pi/2 (-1/2 ln(7)+3)

expand

2 π - \frac{π}{2} (- \frac{1}{2} ln (7) + 3)

2 π + \frac{π}{4} ln (7) - \frac{3 π}{2}

Solution steps

2 π - \frac{π}{2} (- \frac{1}{2} ln (7) + 3)

Expand

- \frac{π}{2} (- \frac{1}{2} ln (7) + 3) : \frac{π}{4} ln (7) - \frac{3 π}{2}

= 2 π + \frac{π}{4} ln (7) - \frac{3 π}{2}

\frac{2 ( x - 4 )}{x - 16}

\frac{s - 1}{( s - 3 ) ( s ^{2} + 2 s + 2 )}

\frac{A x ^{4} + B x ^{3} + 541 x ^{2} - 228 x + 36}{( 3 x - 2 ) ^{2}}

2 (1 + lo g_{2} (3))

(A^{t})^{t}

What is expand 2pi-pi/2 (-1/2 ln(7)+3) ?
The solution to expand 2pi-pi/2 (-1/2 ln(7)+3) is 2pi+pi/4 ln(7)-(3pi)/2