What is expand (2t-5)^2sin(t) ?

The solution to expand (2t-5)^2sin(t) is 4t^2sin(t)-20tsin(t)+25sin(t)

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expand (2t-5)^2sin(t)

expand

(2 t - 5)^{2} sin (t)

4 t^{2} sin (t) - 20 t sin (t) + 25 sin (t)

Solution steps

(2 t - 5)^{2} sin (t)

= sin (t) (2 t - 5)^{2}

Expand

(2 t - 5)^{2} : 4 t^{2} - 20 t + 25

= sin (t) (4 t^{2} - 20 t + 25)

Apply the distributive law:

m (a + b + c) = ma + mb + m c

sin (t) (4 t^{2} - 20 t + 25) = sin (t) \cdot 4 t^{2} + sin (t) (- 20 t) + sin (t) \cdot 25

= sin (t) \cdot 4 t^{2} + sin (t) (- 20 t) + sin (t) \cdot 25

Simplify

sin (t) \cdot 4 t^{2} + sin (t) (- 20 t) + sin (t) \cdot 25 : 4 t^{2} sin (t) - 20 t sin (t) + 25 sin (t)

= 4 t^{2} sin (t) - 20 t sin (t) + 25 sin (t)

(u - 1) u^{\frac{1}{2}}

(2 x + 9 - x)^{2}

\frac{e ^{- x}}{x ( x - 3 ) ( x - 2 )} + \frac{1}{( x - 3 ) ( x - 2 )}

4 xv d v + (3 v^{2} - 1) d x

What is expand (2t-5)^2sin(t) ?
The solution to expand (2t-5)^2sin(t) is 4t^2sin(t)-20tsin(t)+25sin(t)