What is expand (1+x)\times cos(wx) ?

The solution to expand (1+x)\times cos(wx) is cos(wx)+xcos(wx)

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expand (1+x)\times cos(wx)

expand

(1 + x) \cdot cos (w x)

cos (w x) + x cos (w x)

Solution steps

(1 + x) cos (w x)

= cos (w x) (1 + x)

Apply the distributive law:

a (b + c) = ab + a c

cos (w x) (1 + x) = cos (w x) \cdot 1 + cos (w x) x

= cos (w x) \cdot 1 + cos (w x) x

Simplify

cos (w x) \cdot 1 + cos (w x) x : cos (w x) + x cos (w x)

= cos (w x) + x cos (w x)

(x + i - i x^{2})^{2}

\frac{2 s ^{2} + 67}{( s ^{2} + 1 ) ( s + 8 )}

\frac{e ^{z}}{z ( 1 - z ) ^{3}}

(x - \frac{5}{4}) (x - \frac{5}{4})

\frac{d ^{2}}{d ^{2} x} (x^{3} + y^{3} = 1)

What is expand (1+x)\times cos(wx) ?
The solution to expand (1+x)\times cos(wx) is cos(wx)+xcos(wx)