What is expand (1-e^{-t})^2 ?

The solution to expand (1-e^{-t})^2 is 1-2e^{-t}+e^{-2t}

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expand (1-e^{-t})^2

expand

(1 - e^{- t})^{2}

1 - 2 e^{- t} + e^{- 2 t}

Solution steps

(1 - e^{- t})^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

a = 1, b = e^{- t}

= 1^{2} - 2 \cdot 1 \cdot e^{- t} + (e^{- t})^{2}

Simplify

1^{2} - 2 \cdot 1 \cdot e^{- t} + (e^{- t})^{2} : 1 - 2 e^{- t} + e^{- 2 t}

= 1 - 2 e^{- t} + e^{- 2 t}

(t^{2} - e^{5 t} + 13) \cdot H (t - θ)

(a + bi + 1)^{2}

(x^{2} + 3 - 2) \times (x^{2} + 3 + 2)

\frac{( t - 3 ) ^{2}}{4}

A (- 1, 8) e B (- 5, - 1)

What is expand (1-e^{-t})^2 ?
The solution to expand (1-e^{-t})^2 is 1-2e^{-t}+e^{-2t}