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Popular >

d/(dt)((s)(5t^2-3sec(t)+2e^t))

Solution

\frac{d}{d t} ((s) (5 t^{2} - 3 sec (t) + 2 e^{t}))

Solution

s (10 t - 3 sec (t) tan (t) + 2 e^{t})

Solution steps

\frac{d}{d t} ((s) (5 t^{2} - 3 sec (t) + 2 e^{t}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= s \frac{d}{d t} (5 t^{2} - 3 sec (t) + 2 e^{t})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= s (\frac{d}{d t} (5 t^{2}) - \frac{d}{d t} (3 sec (t)) + \frac{d}{d t} (2 e^{t}))

\frac{d}{d t} (5 t^{2}) = 10 t

\frac{d}{d t} (3 sec (t)) = 3 sec (t) tan (t)

\frac{d}{d t} (2 e^{t}) = 2 e^{t}

= s (10 t - 3 sec (t) tan (t) + 2 e^{t})

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Frequently Asked Questions (FAQ)

What is the d/(dt)((s)(5t^2-3sec(t)+2e^t)) ?
The d/(dt)((s)(5t^2-3sec(t)+2e^t)) is s(10t-3sec(t)tan(t)+2e^t)
What is the first d/(dt)((s)(5t^2-3sec(t)+2e^t)) ?
The first d/(dt)((s)(5t^2-3sec(t)+2e^t)) is s(10t-3sec(t)tan(t)+2e^t)