What is expand (2-x^2)sin(2x+1) ?

The solution to expand (2-x^2)sin(2x+1) is 2sin(2x+1)-x^2sin(2x+1)

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expand (2-x^2)sin(2x+1)

expand

(2 - x^{2}) sin (2 x + 1)

2 sin (2 x + 1) - x^{2} sin (2 x + 1)

Solution steps

(2 - x^{2}) sin (2 x + 1)

= sin (2 x + 1) (2 - x^{2})

Apply the distributive law:

a (b - c) = ab - a c

sin (2 x + 1) (2 - x^{2}) = sin (2 x + 1) \cdot 2 - sin (2 x + 1) x^{2}

= sin (2 x + 1) \cdot 2 - sin (2 x + 1) x^{2}

= 2 sin (2 x + 1) - x^{2} sin (2 x + 1)

\frac{2}{( x + 1 ) ( x - 1 )}

\frac{2 x + 5}{( x - 3 ) ^{2}}

(6 x + 3 y = 1, 2) (3 x + y = 5)

(- 1)^{x + 1} (\frac{π ^{3}}{x} - \frac{6 π}{x ^{3}})

What is expand (2-x^2)sin(2x+1) ?
The solution to expand (2-x^2)sin(2x+1) is 2sin(2x+1)-x^2sin(2x+1)