What is (t-1+(t^2)/2)(1+t) ?

The solution to (t-1+(t^2)/2)(1+t) is ((2t-2+t^2)(1+t))/2

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simplify (t-1+(t^2)/2)(1+t)

simplify

(t - 1 + \frac{t ^{2}}{2}) (1 + t)

\frac{( 2 t - 2 + t ^{2} ) ( 1 + t )}{2}

Solution steps

(t - 1 + \frac{t ^{2}}{2}) (1 + t)

Simplify

t - 1 + \frac{t ^{2}}{2} : \frac{2 t - 2 + t ^{2}}{2}

= \frac{2 t - 2 + t ^{2}}{2} (1 + t)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 2 t - 2 + t ^{2} ) ( 1 + t )}{2}

(- 2 cos (x) - 4)^{2}

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1 + \frac{K \cdot 885.4}{( s + 40 ) ( s ^{2} + 98 )}

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\frac{4000 ( s ^{2} + 4 s + 4 )}{s ( s + 10 ) ( s + 100 )}

What is (t-1+(t^2)/2)(1+t) ?
The solution to (t-1+(t^2)/2)(1+t) is ((2t-2+t^2)(1+t))/2