What is expand ((2h-a)(2h-3a))/2 ?

The solution to expand ((2h-a)(2h-3a))/2 is 2h^2-4ah+(3a^2)/2

Popular >

expand ((2h-a)(2h-3a))/2

expand

\frac{( 2 h - a ) ( 2 h - 3 a )}{2}

2 h^{2} - 4 ah + \frac{3 a ^{2}}{2}

Solution steps

\frac{( 2 h - a ) ( 2 h - 3 a )}{2}

Expand

(2 h - a) (2 h - 3 a) : 4 h^{2} - 8 ah + 3 a^{2}

= \frac{4 h ^{2} - 8 ah + 3 a ^{2}}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 h ^{2} - 8 ah + 3 a ^{2}}{2} = \frac{4 h ^{2}}{2} - \frac{8 ah}{2} + \frac{3 a ^{2}}{2}

= \frac{4 h ^{2}}{2} - \frac{8 ah}{2} + \frac{3 a ^{2}}{2}

Divide the numbers:

\frac{4}{2} = 2

= 2 h^{2} - \frac{8 ah}{2} + \frac{3 a ^{2}}{2}

Divide the numbers:

\frac{8}{2} = 4

= 2 h^{2} - 4 ah + \frac{3 a ^{2}}{2}

\frac{3 ( x ^{2} + 1 ) ^{\frac{5}{2}} - 5 ( x ^{2} + 1 ) ^{\frac{3}{2}}}{15}

(3 - e^{2 x^{2} + x})^{4}

\frac{2}{3} (a + 3) (b + (- \frac{4}{3}))

\frac{1}{81} (2 + s)^{4}

e^{(y + 1)^{2}} ((y^{2} + y) d x - x d y)

What is expand ((2h-a)(2h-3a))/2 ?
The solution to expand ((2h-a)(2h-3a))/2 is 2h^2-4ah+(3a^2)/2