What is expand 1/((s+1)(s^2-1)) ?

The solution to expand 1/((s+1)(s^2-1)) is 1/(s^3-s+s^2-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 1/((s+1)(s^2-1))

expand

\frac{1}{( s + 1 ) ( s ^{2} - 1 )}

\frac{1}{s ^{3} - s + s ^{2} - 1}

Solution steps

\frac{1}{( s + 1 ) ( s ^{2} - 1 )}

Expand

(s + 1) (s^{2} - 1) : s^{3} - s + s^{2} - 1

= \frac{1}{s ^{3} - s + s ^{2} - 1}

(1 + 2 sin (θ))^{2}

\frac{x ^{2} y ^{4} ( 6 x - 1 ) ^{2}}{4}

\frac{d}{d θ} ((x (θ)) (a (θ - sin (θ))))

\frac{k ( s + 4 )}{s ( s + 1 ) ( s + 3 )}

What is expand 1/((s+1)(s^2-1)) ?
The solution to expand 1/((s+1)(s^2-1)) is 1/(s^3-s+s^2-1)