What is expand (3sin^2(θ))(1+sin^2(θ)) ?

The solution to expand (3sin^2(θ))(1+sin^2(θ)) is 3sin^2(θ)+3sin^4(θ)

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expand (3sin^2(θ))(1+sin^2(θ))

expand

(3 sin^{2} (θ)) (1 + sin^{2} (θ))

3 sin^{2} (θ) + 3 sin^{4} (θ)

Solution steps

(3 sin^{2} (θ)) (1 + sin^{2} (θ))

Apply the distributive law:

a (b + c) = ab + a c

(3 sin^{2} (θ)) (1 + sin^{2} (θ)) = 3 sin^{2} (θ) \cdot 1 + 3 sin^{2} (θ) sin^{2} (θ)

= 3 sin^{2} (θ) \cdot 1 + 3 sin^{2} (θ) sin^{2} (θ)

Simplify

3 sin^{2} (θ) \cdot 1 + 3 sin^{2} (θ) sin^{2} (θ) : 3 sin^{2} (θ) + 3 sin^{4} (θ)

= 3 sin^{2} (θ) + 3 sin^{4} (θ)

3 (ln (- 1) + 1)

(\frac{( n + 1 ) ( n + 2 )}{2})^{2}

x^{\frac{1}{2}} (x^{\frac{3}{2}} - 4) (x^{\frac{1}{2}} + 4)

(1 - ln (x)) d y

x + 4 (x - 4 + 3 x - 4)

What is expand (3sin^2(θ))(1+sin^2(θ)) ?
The solution to expand (3sin^2(θ))(1+sin^2(θ)) is 3sin^2(θ)+3sin^4(θ)