What is (\partial)/(\partial u)((x)(u^2-v^2)) ?

The answer to (\partial)/(\partial u)((x)(u^2-v^2)) is 2xu

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(\partial)/(\partial u)((x)(u^2-v^2))

\frac{\partial}{\partial u} ((x) (u^{2} - v^{2}))

2 xu

Solution steps

\frac{\partial}{\partial u} ((x) (u^{2} - v^{2}))

Treat

x, v

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{\partial}{\partial u} (u^{2} - v^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= x (\frac{\partial}{\partial u} (u^{2}) - \frac{\partial}{\partial u} (v^{2}))

\frac{\partial}{\partial u} (u^{2}) = 2 u

\frac{\partial}{\partial u} (v^{2}) = 0

= x (2 u - 0)

Simplify

= 2 xu

8.4 \cdot (1 - \frac{1}{3} \cdot (\frac{63 , 5 - 40}{65 - 40}))

(i - 2)^{4}

(e^{x} + e^{- x})^{2} \cdot e^{2 x} \cdot (e^{x} - 1)^{2}

(t^{2} + 1) (2 t^{2} + 1)

- \frac{x ^{3} + 6 x ^{2} + 16 x - 32}{2 ( x ^{2} + 4 ) ( x ^{2} + 16 )}

What is (\partial)/(\partial u)((x)(u^2-v^2)) ?
The answer to (\partial)/(\partial u)((x)(u^2-v^2)) is 2xu