What is (2u^2+2v^2)(sqrt(2u^2+2v^2+4)) ?

The solution to (2u^2+2v^2)(sqrt(2u^2+2v^2+4)) is (2u^2+2v^2)sqrt(2u^2+2v^2+4)

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simplify (2u^2+2v^2)(sqrt(2u^2+2v^2+4))

simplify

(2 u^{2} + 2 v^{2}) (2 u^{2} + 2 v^{2} + 4)

(2 u^{2} + 2 v^{2}) 2 u^{2} + 2 v^{2} + 4

Solution steps

(2 u^{2} + 2 v^{2}) (2 u^{2} + 2 v^{2} + 4)

Apply rule:

(a) = a

(2 u^{2} + 2 v^{2} + 4) = 2 u^{2} + 2 v^{2} + 4

= (2 u^{2} + 2 v^{2}) 2 u^{2} + 2 v^{2} + 4

\frac{( 1 )}{( - 2 x ^{(2)} + 2 y ) ( 8 x + 2 y )}

\frac{2 t ^{2} + t + 1}{( x - 3 ) ( 2 x ^{2} + 1 )}

5 (14 ln (2) - 3)

u (t - 2 π) sin (t)

(1 - x^{2} - y^{2}) \cdot (1 + 4 x^{2} + 4 y^{2})

What is (2u^2+2v^2)(sqrt(2u^2+2v^2+4)) ?
The solution to (2u^2+2v^2)(sqrt(2u^2+2v^2+4)) is (2u^2+2v^2)sqrt(2u^2+2v^2+4)