What is expand log_{10}(sqrt((x-1)/(x+1))) ?

The solution to expand log_{10}(sqrt((x-1)/(x+1))) is 1/2 log_{10}((x-1)/(x+1))

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expand log_{10}(sqrt((x-1)/(x+1)))

expand

lo g_{10} (\frac{x - 1}{x + 1})

\frac{1}{2} lo g_{10} (\frac{x - 1}{x + 1})

Solution steps

lo g_{10} (\frac{x - 1}{x + 1})

Rewrite as

= lo g_{10} ((\frac{x - 1}{x + 1})^{\frac{1}{2}})

Apply log rule

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x),

assuming

x \geq 0

= \frac{1}{2} lo g_{10} (\frac{x - 1}{x + 1})

H (t - b) (t - π)

cot (θ) (cos (θ) + tan (θ), θ)

(- 0.05 + 0.25 cos (θ)) (cos (θ) - 1)

(x^{4} - 4 x)^{\frac{1}{2}} \cdot 2 (x^{3} - 1)

(sin (θ) + tan (θ))^{2}

What is expand log_{10}(sqrt((x-1)/(x+1))) ?
The solution to expand log_{10}(sqrt((x-1)/(x+1))) is 1/2 log_{10}((x-1)/(x+1))