What is expand (sin(4θ))/(2cos^2(θ)(4cos^2(θ)-3)) ?

The solution to expand (sin(4θ))/(2cos^2(θ)(4cos^2(θ)-3)) is (sin(4θ))/(8cos^4(θ)-6cos^2(θ))

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expand (sin(4θ))/(2cos^2(θ)(4cos^2(θ)-3))

expand

\frac{sin ( 4 θ )}{2 cos ^{2} ( θ ) ( 4 cos ^{2} ( θ ) - 3 )}

\frac{sin ( 4 θ )}{8 cos ^{4} ( θ ) - 6 cos ^{2} ( θ )}

Solution steps

\frac{sin ( 4 θ )}{2 cos ^{2} ( θ ) ( 4 cos ^{2} ( θ ) - 3 )}

Expand

2 cos^{2} (θ) (4 cos^{2} (θ) - 3) : 8 cos^{4} (θ) - 6 cos^{2} (θ)

= \frac{sin ( 4 θ )}{8 cos ^{4} ( θ ) - 6 cos ^{2} ( θ )}

x + sin (y) - cos (y) d x + x (sin (y) + cos (y) d y = 0)

(10 x + 2)^{3} (x - i) (8 x^{4} - 4) (9 x^{2} + 12 x + 3)

2 x e^{7 x + 2} + e^{7 x + 2} \cdot 7 (x^{2} + 7)

\frac{4}{9} (x - 1) (x - 0.9512)

lo g_{9} (x) (x + 2)

What is expand (sin(4θ))/(2cos^2(θ)(4cos^2(θ)-3)) ?
The solution to expand (sin(4θ))/(2cos^2(θ)(4cos^2(θ)-3)) is (sin(4θ))/(8cos^4(θ)-6cos^2(θ))