What is expand log_{9}(x)(x+2) ?

The solution to expand log_{9}(x)(x+2) is xlog_{9}(x)+log_{3}(x)

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expand log_{9}(x)(x+2)

expand

lo g_{9} (x) (x + 2)

x lo g_{9} (x) + lo g_{3} (x)

Solution steps

lo g_{9} (x) (x + 2)

Apply the distributive law:

a (b + c) = ab + a c

lo g_{9} (x) (x + 2) = lo g_{9} (x) x + lo g_{9} (x) \cdot 2

= lo g_{9} (x) x + lo g_{9} (x) \cdot 2

Simplify

lo g_{9} (x) x + lo g_{9} (x) \cdot 2 : x lo g_{9} (x) + lo g_{3} (x)

= x lo g_{9} (x) + lo g_{3} (x)

(y + 5) (y - 5)

(2 t + 1) d t

y (y + x + 1) d x + (x + 2 y) d y

\frac{7 x + 32}{( x + 1 ) ( x + 6 )}

(f \circ g) (2 x + 3) (x^{2} - 1)

What is expand log_{9}(x)(x+2) ?
The solution to expand log_{9}(x)(x+2) is xlog_{9}(x)+log_{3}(x)