What is expand ((y^2-1)(3x^2+8x))/y ?

The solution to expand ((y^2-1)(3x^2+8x))/y is 3yx^2+8yx-(3x^2)/y-(8x)/y

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expand ((y^2-1)(3x^2+8x))/y

expand

\frac{( y ^{2} - 1 ) ( 3 x ^{2} + 8 x )}{y}

3 y x^{2} + 8 y x - \frac{3 x ^{2}}{y} - \frac{8 x}{y}

Solution steps

\frac{( y ^{2} - 1 ) ( 3 x ^{2} + 8 x )}{y}

Expand

(y^{2} - 1) (3 x^{2} + 8 x) : 3 y^{2} x^{2} + 8 y^{2} x - 3 x^{2} - 8 x

= \frac{3 y ^{2} x ^{2} + 8 y ^{2} x - 3 x ^{2} - 8 x}{y}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 y ^{2} x ^{2} + 8 y ^{2} x - 3 x ^{2} - 8 x}{y} = \frac{3 y ^{2} x ^{2}}{y} + \frac{8 y ^{2} x}{y} - \frac{3 x ^{2}}{y} - \frac{8 x}{y}

= \frac{3 y ^{2} x ^{2}}{y} + \frac{8 y ^{2} x}{y} - \frac{3 x ^{2}}{y} - \frac{8 x}{y}

Cancel

\frac{3 y ^{2} x ^{2}}{y} : 3 y x^{2}

= 3 y x^{2} + \frac{8 y ^{2} x}{y} - \frac{3 x ^{2}}{y} - \frac{8 x}{y}

Cancel

\frac{8 y ^{2} x}{y} : 8 y x

= 3 y x^{2} + 8 y x - \frac{3 x ^{2}}{y} - \frac{8 x}{y}

- (\frac{5 s ^{2} - 2 s + 1}{s ( s + 3 ) ( s - 1 )})

x^{2} y^{''} (x) - x (x + 2) y^{'} (x) + (x + 2) y

sin (a) (tan (a) + csc (a))

(x + \frac{3}{2}) (x^{2} + 3 x + y^{2})

(5 - 11) (7 + 23)

What is expand ((y^2-1)(3x^2+8x))/y ?
The solution to expand ((y^2-1)(3x^2+8x))/y is 3yx^2+8yx-(3x^2)/y-(8x)/y