What is expand (2sin(x)+1)(2sin(x)-3) ?

The solution to expand (2sin(x)+1)(2sin(x)-3) is 4sin^2(x)-4sin(x)-3

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expand (2sin(x)+1)(2sin(x)-3)

expand

(2 sin (x) + 1) (2 sin (x) - 3)

4 sin^{2} (x) - 4 sin (x) - 3

Solution steps

(2 sin (x) + 1) (2 sin (x) - 3)

Apply FOIL method

(2 sin (x) + 1) (2 sin (x) - 3) : 4 sin^{2} (x) - 4 sin (x) - 3

= 4 sin^{2} (x) - 4 sin (x) - 3

(1 + sin (θ))^{2} sec^{2} (θ)

(csc (θ) + sec (θ))^{2}

(n + 1)^{2} (\frac{2}{3})^{n}

9 z^{2} (4 e + 7 f) + 4 e + 7 f

(5 a + b^{5}) l e f t (5 a - b^{5})

What is expand (2sin(x)+1)(2sin(x)-3) ?
The solution to expand (2sin(x)+1)(2sin(x)-3) is 4sin^2(x)-4sin(x)-3