What is expand ((4x+9)^{3/2}-27)/6 ?

The solution to expand ((4x+9)^{3/2}-27)/6 is ((4x+9)^{3/2})/6-9/2

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expand ((4x+9)^{3/2}-27)/6

expand

\frac{( 4 x + 9 ) ^{\frac{3}{2}} - 27}{6}

\frac{( 4 x + 9 ) ^{\frac{3}{2}}}{6} - \frac{9}{2}

Solution steps

\frac{( 4 x + 9 ) ^{\frac{3}{2}} - 27}{6}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{( 4 x + 9 ) ^{\frac{3}{2}} - 27}{6} = \frac{( 4 x + 9 ) ^{\frac{3}{2}}}{6} - \frac{27}{6}

= \frac{( 4 x + 9 ) ^{\frac{3}{2}}}{6} - \frac{27}{6}

Cancel

\frac{27}{6} : \frac{9}{2}

= \frac{( 4 x + 9 ) ^{\frac{3}{2}}}{6} - \frac{9}{2}

(cos (t) - 4 sin (t))^{2}

\frac{36 x}{( 9 - x ^{2} ) ^{2}}

(- b + b^{2} + 4 a c)^{2}

\frac{1}{( 2 x )} 5

\frac{1}{( x - a ) ^{2}}

What is expand ((4x+9)^{3/2}-27)/6 ?
The solution to expand ((4x+9)^{3/2}-27)/6 is ((4x+9)^{3/2})/6-9/2