What is (-b+sqrt(b^2+4ac))^2 ?

The solution to (-b+sqrt(b^2+4ac))^2 is 2b^2-2bsqrt(b^2+4ac)+4ac

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (-b+sqrt(b^2+4ac))^2

simplify

(- b + b^{2} + 4 a c)^{2}

2 b^{2} - 2 b b^{2} + 4 a c + 4 a c

Solution steps

(- b + b^{2} + 4 a c)^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(- b + b^{2} + 4 a c)^{2} = (- b)^{2} + 2 (- b) b^{2} + 4 a c + (b^{2} + 4 a c)^{2}

= (- b)^{2} + 2 (- b) b^{2} + 4 a c + (b^{2} + 4 a c)^{2}

Simplify

(- b)^{2} + 2 (- b) b^{2} + 4 a c + (b^{2} + 4 a c)^{2} : 2 b^{2} - 2 b b^{2} + 4 a c + 4 a c

= 2 b^{2} - 2 b b^{2} + 4 a c + 4 a c

\frac{1}{( 2 x )} 5

\frac{1}{( x - a ) ^{2}}

\frac{( 2 x + 3 ) ( x - 4 )}{8}

\frac{x + 2}{( x - 2 ) ( x + 1 )}

\frac{9 ( - t ^{2} + 9 )}{( t ^{2} + 9 ) ^{2}}

What is (-b+sqrt(b^2+4ac))^2 ?
The solution to (-b+sqrt(b^2+4ac))^2 is 2b^2-2bsqrt(b^2+4ac)+4ac