What are the solutions to the equation 4x^2+76=6x ?

The solutions to the equation 4x^2+76=6x are x= 3/4+i(sqrt(295))/4 ,x= 3/4-i(sqrt(295))/4

Find the zeros of 4x^2+76=6x

The zeros of 4x^2+76=6x are x= 3/4+i(sqrt(295))/4 ,x= 3/4-i(sqrt(295))/4

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4 x^{2} + 76 = 6 x

x = \frac{3}{4} + i \frac{295}{4}, x = \frac{3}{4} - i \frac{295}{4}

Solution steps

4 x^{2} + 76 = 6 x

Move

6 x

to the left side

4 x^{2} + 76 - 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 6 x + 76 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 4 \cdot 76}{2 \cdot 4}

Simplify

(- 6)^{2} - 4 \cdot 4 \cdot 76 : 2295 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 295 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 295 i}{2 \cdot 4}, x_{2} = \frac{- ( - 6 ) - 2 295 i}{2 \cdot 4}

x = \frac{- ( - 6 ) + 2 295 i}{2 \cdot 4} : \frac{3}{4} + i \frac{295}{4}

x = \frac{- ( - 6 ) - 2 295 i}{2 \cdot 4} : \frac{3}{4} - i \frac{295}{4}

The solutions to the quadratic equation are:

x = \frac{3}{4} + i \frac{295}{4}, x = \frac{3}{4} - i \frac{295}{4}

- x^{2} + 16 x

5 (v + 1) - v = 3 (v - 1) + 7

\frac{( \frac{3}{2} ) ^{- \frac{2}{3}}}{( \frac{2}{81} ) ^{\frac{2}{3}}}

8 - \frac{4}{5} (x + 3) = 2 x

What are the solutions to the equation 4x^2+76=6x ?
The solutions to the equation 4x^2+76=6x are x= 3/4+i(sqrt(295))/4 ,x= 3/4-i(sqrt(295))/4
Find the zeros of 4x^2+76=6x
The zeros of 4x^2+76=6x are x= 3/4+i(sqrt(295))/4 ,x= 3/4-i(sqrt(295))/4