What is expand (40+(40)/(ln(4x^2+40)))(x) ?

The solution to expand (40+(40)/(ln(4x^2+40)))(x) is 40x+(40x)/(ln(4x^2+40))

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expand (40+(40)/(ln(4x^2+40)))(x)

expand

(40 + \frac{40}{ln ( 4 x ^{2} + 40 )}) (x)

40 x + \frac{40 x}{ln ( 4 x ^{2} + 40 )}

Solution steps

(40 + \frac{40}{ln ( 4 x ^{2} + 40 )}) (x)

= (x) (40 + \frac{40}{ln ( 4 x ^{2} + 40 )})

Apply the distributive law:

a (b + c) = ab + a c

a = (x), b = 40, c = \frac{40}{ln ( 4 x ^{2} + 40 )}

= (x) \cdot 40 + (x) \frac{40}{ln ( 4 x ^{2} + 40 )}

= 40 (x) + \frac{40}{ln ( 4 x ^{2} + 40 )} (x)

Simplify

40 (x) + \frac{40}{ln ( 4 x ^{2} + 40 )} (x) : 40 x + \frac{40 x}{ln ( 4 x ^{2} + 40 )}

= 40 x + \frac{40 x}{ln ( 4 x ^{2} + 40 )}

4 (1 + 3)

(e^{- α a_{1}} - 1) (e^{- β b_{1}} - 1)

\frac{( x ^{4} )}{( 4 ( x ^{2} + 1 ) )}

- \frac{( x - 2 ) ( x + 6 )}{( x - 5 ) ( x + 1 )}

\frac{3}{( x - 7 ) ^{2}}

What is expand (40+(40)/(ln(4x^2+40)))(x) ?
The solution to expand (40+(40)/(ln(4x^2+40)))(x) is 40x+(40x)/(ln(4x^2+40))