What is expand \H(t-a)(t-a) ?

The solution to expand \H(t-a)(t-a) is t\H(t-a)-a\H(t-a)

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expand \H(t-a)(t-a)

expand

H (t - a) (t - a)

t H (t - a) - a H (t - a)

Solution steps

H (t - a) (t - a)

Apply the distributive law:

a (b - c) = ab - a c

a = H (t - a), b = t, c = a

= H (t - a) t - H (t - a) a

= t H (t - a) - a H (t - a)

H (t - a) (t - b)

(3 - 2 x + 4)^{2}

(x^{2} + y^{2}) (y, x, e^{z}) + (x y + e^{z}) (2 x, 2 y, 0)

arccos (0)

\frac{18.1 x ^{2} + 58.1}{x ^{2} ( x + 11.2 )}

What is expand \H(t-a)(t-a) ?
The solution to expand \H(t-a)(t-a) is t\H(t-a)-a\H(t-a)