What is expand (x^2+4x+1)/((x-1)(x+1)(x+3)) ?

The solution to expand (x^2+4x+1)/((x-1)(x+1)(x+3)) is (x^2+4x+1)/(x^3+3x^2-x-3)

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expand (x^2+4x+1)/((x-1)(x+1)(x+3))

expand

\frac{x ^{2} + 4 x + 1}{( x - 1 ) ( x + 1 ) ( x + 3 )}

\frac{x ^{2} + 4 x + 1}{x ^{3} + 3 x ^{2} - x - 3}

Solution steps

\frac{x ^{2} + 4 x + 1}{( x - 1 ) ( x + 1 ) ( x + 3 )}

Expand

(x - 1) (x + 1) (x + 3) : x^{3} + 3 x^{2} - x - 3

= \frac{x ^{2} + 4 x + 1}{x ^{3} + 3 x ^{2} - x - 3}

3 (2 - 1)

x^{\frac{4}{5}} (x - 1)

\frac{d}{d t} ((x) (x^{2} y - y^{2}))

(2 - i)^{8}

5 (1 - 2 sin (2 x))

What is expand (x^2+4x+1)/((x-1)(x+1)(x+3)) ?
The solution to expand (x^2+4x+1)/((x-1)(x+1)(x+3)) is (x^2+4x+1)/(x^3+3x^2-x-3)