What is |-bsin(t)+bcos(t)+sqrt((1+b)(1-b))| ?

The solution to |-bsin(t)+bcos(t)+sqrt((1+b)(1-b))| is |-bsin(t)+bcos(t)+sqrt(1+b)sqrt(1-b)|

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify |-bsin(t)+bcos(t)+sqrt((1+b)(1-b))|

simplify

- b sin (t) + b cos (t) + (1 + b) (1 - b)

- b sin (t) + b cos (t) + 1 + b 1 - b

Solution steps

- b sin (t) + b cos (t) + (1 + b) (1 - b)

Apply radical rule:

ab = a b,

assuming

a \geq 0, b \geq 0

(1 + b) (1 - b) = 1 + b 1 - b

= - b sin (t) + b cos (t) + 1 + b 1 - b

(3 + 2 i) (1 + 7 i) (= - 11 + 23 i)

(x + \frac{7}{2}) (x - 3)

sin (\frac{π}{3} - θ)

(\frac{1 + cos ( 2 x )}{2})^{2}

- 2 a (- 2 a e^{- a x^{2}} x^{2} + e^{- a x^{2}})

What is |-bsin(t)+bcos(t)+sqrt((1+b)(1-b))| ?
The solution to |-bsin(t)+bcos(t)+sqrt((1+b)(1-b))| is |-bsin(t)+bcos(t)+sqrt(1+b)sqrt(1-b)|