What is expand (3(x+4))/(b+2)-(2(x+7))/(b+4) ?

The solution to expand (3(x+4))/(b+2)-(2(x+7))/(b+4) is (bx+8x+20-2b)/(b^2+6b+8)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (3(x+4))/(b+2)-(2(x+7))/(b+4)

expand

\frac{3 ( x + 4 )}{b + 2} - \frac{2 ( x + 7 )}{b + 4}

\frac{b x + 8 x + 20 - 2 b}{b ^{2} + 6 b + 8}

Solution steps

\frac{3 ( x + 4 )}{b + 2} - \frac{2 ( x + 7 )}{b + 4}

Expand

3 (x + 4) : 3 x + 12

= \frac{3 x + 12}{b + 2} - \frac{2 ( x + 7 )}{b + 4}

Expand

2 (x + 7) : 2 x + 14

= \frac{3 x + 12}{b + 2} - \frac{2 x + 14}{b + 4}

Least Common Multiplier of

b + 2, b + 4 : (b + 2) (b + 4)

Adjust Fractions based on the LCM

= \frac{( 3 x + 12 ) ( b + 4 )}{( b + 2 ) ( b + 4 )} - \frac{( 2 x + 14 ) ( b + 2 )}{( b + 4 ) ( b + 2 )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{( 3 x + 12 ) ( b + 4 ) - ( 2 x + 14 ) ( b + 2 )}{( b + 2 ) ( b + 4 )}

Expand

(b + 2) (b + 4) : b^{2} + 6 b + 8

= \frac{( 3 x + 12 ) ( b + 4 ) - ( 2 x + 14 ) ( b + 2 )}{b ^{2} + 6 b + 8}

Expand

(3 x + 12) (b + 4) - (2 x + 14) (b + 2) : b x + 8 x + 20 - 2 b

= \frac{b x + 8 x + 20 - 2 b}{b ^{2} + 6 b + 8}

\frac{8}{( 1 - 6 x ) ^{2}}

\frac{3 ( 2 x - 1 )}{x ^{3}}

(e^{z} - e^{- z})^{2}

(u cos (θ) - \frac{u a ^{2} cos ( θ )}{r ^{2}})^{2}

2 (3 e^{3 y} y - e^{3 y})

What is expand (3(x+4))/(b+2)-(2(x+7))/(b+4) ?
The solution to expand (3(x+4))/(b+2)-(2(x+7))/(b+4) is (bx+8x+20-2b)/(b^2+6b+8)