What is expand (-4x^2+4x-3)/((2x-1)^2) ?

The solution to expand (-4x^2+4x-3)/((2x-1)^2) is (-4x^2+4x-3)/(4x^2-4x+1)

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expand (-4x^2+4x-3)/((2x-1)^2)

expand

\frac{- 4 x ^{2} + 4 x - 3}{( 2 x - 1 ) ^{2}}

\frac{- 4 x ^{2} + 4 x - 3}{4 x ^{2} - 4 x + 1}

Solution steps

\frac{- 4 x ^{2} + 4 x - 3}{( 2 x - 1 ) ^{2}}

(2 x - 1)^{2} = 4 x^{2} - 4 x + 1

= \frac{- 4 x ^{2} + 4 x - 3}{4 x ^{2} - 4 x + 1}

(0, - 3, 1) (t^{2})

P (\frac{3}{2}, - \frac{1}{2}) Q (\frac{3}{2}, \frac{19}{2})

r^{2} (sin^{2} (x) sin^{2} (y) + cos^{2} (x))

(a - b)^{12}

\frac{- x + 11}{3 x ( 4 x - 3 )}

What is expand (-4x^2+4x-3)/((2x-1)^2) ?
The solution to expand (-4x^2+4x-3)/((2x-1)^2) is (-4x^2+4x-3)/(4x^2-4x+1)