What is expand (0,-3,1)(t^2) ?

The solution to expand (0,-3,1)(t^2) is 0*(t^2),-3(t^2),1

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expand (0,-3,1)(t^2)

expand

(0, - 3, 1) (t^{2})

0 \cdot (t^{2}), - 3 (t^{2}), 1

Solution steps

(0, - 3, 1) (t^{2})

= (0, - 3 \cdot 1,) (t^{2})

Apply the distributive law:

a (b - c) = ab - a c

a = (t^{2}), b = 0,, c = 3, 1

= (t^{2}) \cdot 0, - (t^{2}) \cdot 3, 1

= 0 \cdot (t^{2}), - 3 (t^{2}), 1

P (\frac{3}{2}, - \frac{1}{2}) Q (\frac{3}{2}, \frac{19}{2})

r^{2} (sin^{2} (x) sin^{2} (y) + cos^{2} (x))

(a - b)^{12}

\frac{- x + 11}{3 x ( 4 x - 3 )}

(\frac{π}{4} + \frac{1}{2}) (x - 1)

What is expand (0,-3,1)(t^2) ?
The solution to expand (0,-3,1)(t^2) is 0*(t^2),-3(t^2),1