What is expand (pi/4+1/2)(x-1) ?

The solution to expand (pi/4+1/2)(x-1) is (pix)/4+x/2-pi/4-1/2

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expand (pi/4+1/2)(x-1)

expand

(\frac{π}{4} + \frac{1}{2}) (x - 1)

\frac{π x}{4} + \frac{x}{2} - \frac{π}{4} - \frac{1}{2}

Solution steps

(\frac{π}{4} + \frac{1}{2}) (x - 1)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = \frac{π}{4}, b = \frac{1}{2}, c = x, d = - 1

= \frac{π}{4} x + \frac{π}{4} (- 1) + \frac{1}{2} x + \frac{1}{2} (- 1)

Apply minus-plus rules

+ (- a) = - a

= \frac{π}{4} x - 1 \cdot \frac{π}{4} + \frac{1}{2} x - 1 \cdot \frac{1}{2}

Simplify

\frac{π}{4} x - 1 \cdot \frac{π}{4} + \frac{1}{2} x - 1 \cdot \frac{1}{2} : \frac{π x}{4} + \frac{x}{2} - \frac{π}{4} - \frac{1}{2}

= \frac{π x}{4} + \frac{x}{2} - \frac{π}{4} - \frac{1}{2}

(1 + 2 y)^{2}

(sin (x) - 1) (cos (x) - \frac{1}{2})

\frac{d}{d x} ((2) (x - 3 + \frac{2}{x + 1}))

(a^{2} + b^{2} - 2 ab) (a^{2} + b^{2} + 2 ab)

π \times r \times (9 + r)

What is expand (pi/4+1/2)(x-1) ?
The solution to expand (pi/4+1/2)(x-1) is (pix)/4+x/2-pi/4-1/2