What is (sin(x)-1)(cos(x)-1/2) ?

The solution to (sin(x)-1)(cos(x)-1/2) is ((sin(x)-1)(2cos(x)-1))/2

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simplify (sin(x)-1)(cos(x)-1/2)

simplify

(sin (x) - 1) (cos (x) - \frac{1}{2})

\frac{( sin ( x ) - 1 ) ( 2 cos ( x ) - 1 )}{2}

Solution steps

(sin (x) - 1) (cos (x) - \frac{1}{2})

Simplify

cos (x) - \frac{1}{2} : \frac{2 cos ( x ) - 1}{2}

= (sin (x) - 1) \frac{2 cos ( x ) - 1}{2}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( sin ( x ) - 1 ) ( 2 cos ( x ) - 1 )}{2}

\frac{d}{d x} ((2) (x - 3 + \frac{2}{x + 1}))

(a^{2} + b^{2} - 2 ab) (a^{2} + b^{2} + 2 ab)

π \times r \times (9 + r)

- \frac{2 x ( - x ^{2} - 27 )}{( x ^{2} - 9 ) ^{3}}

\frac{n ^{2} \cdot ( n - 1 ) \cdot ( n + 1 )}{12}

What is (sin(x)-1)(cos(x)-1/2) ?
The solution to (sin(x)-1)(cos(x)-1/2) is ((sin(x)-1)(2cos(x)-1))/2