What is ((2x^2y^2)/3+2)(xy+4x) ?

The solution to ((2x^2y^2)/3+2)(xy+4x) is ((6+2x^2y^2)(xy+4x))/3

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simplify ((2x^2y^2)/3+2)(xy+4x)

simplify

(\frac{2 x ^{2} y ^{2}}{3} + 2) (x y + 4 x)

\frac{( 6 + 2 x ^{2} y ^{2} ) ( x y + 4 x )}{3}

Solution steps

(\frac{2 x ^{2} y ^{2}}{3} + 2) (x y + 4 x)

Join

\frac{2 x ^{2} y ^{2}}{3} + 2 : \frac{6 + 2 x ^{2} y ^{2}}{3}

= \frac{6 + 2 x ^{2} y ^{2}}{3} (x y + 4 x)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 6 + 2 x ^{2} y ^{2} ) ( x y + 4 x )}{3}

\frac{d}{d x} ((x - 1) (x - 7)^{3}) + 10

(2 + 4 - x^{2} - y^{2})^{2}

- \frac{r ( a - bk )}{b c k}

(- 4)^{3}

(x + i (- x + 2))^{2}

What is ((2x^2y^2)/3+2)(xy+4x) ?
The solution to ((2x^2y^2)/3+2)(xy+4x) is ((6+2x^2y^2)(xy+4x))/3