What is expand (k^3+5k^2+6k+4)/(2k(k+2)^2) ?

The solution to expand (k^3+5k^2+6k+4)/(2k(k+2)^2) is (k^3+5k^2+6k+4)/(2k^3+8k^2+8k)

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expand (k^3+5k^2+6k+4)/(2k(k+2)^2)

expand

\frac{k ^{3} + 5 k ^{2} + 6 k + 4}{2 k ( k + 2 ) ^{2}}

\frac{k ^{3} + 5 k ^{2} + 6 k + 4}{2 k ^{3} + 8 k ^{2} + 8 k}

Solution steps

\frac{k ^{3} + 5 k ^{2} + 6 k + 4}{2 k ( k + 2 ) ^{2}}

(k + 2)^{2} = k^{2} + 4 k + 4

= \frac{k ^{3} + 5 k ^{2} + 6 k + 4}{2 k ( k ^{2} + 4 k + 4 )}

Expand

2 k (k^{2} + 4 k + 4) : 2 k^{3} + 8 k^{2} + 8 k

= \frac{k ^{3} + 5 k ^{2} + 6 k + 4}{2 k ^{3} + 8 k ^{2} + 8 k}

5 (5 + y 15)

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What is expand (k^3+5k^2+6k+4)/(2k(k+2)^2) ?
The solution to expand (k^3+5k^2+6k+4)/(2k(k+2)^2) is (k^3+5k^2+6k+4)/(2k^3+8k^2+8k)