What is expand-(z^2(-2z+6)^2)/9 ?

The solution to expand-(z^2(-2z+6)^2)/9 is -(4z^4)/9+(8z^3)/3-4z^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-(z^2(-2z+6)^2)/9

expand

- \frac{z ^{2} ( - 2 z + 6 ) ^{2}}{9}

- \frac{4 z ^{4}}{9} + \frac{8 z ^{3}}{3} - 4 z^{2}

Solution steps

- \frac{z ^{2} ( - 2 z + 6 ) ^{2}}{9}

(- 2 z + 6)^{2} = 4 z^{2} - 24 z + 36

= - \frac{z ^{2} ( 4 z ^{2} - 24 z + 36 )}{9}

Expand

z^{2} (4 z^{2} - 24 z + 36) : 4 z^{4} - 24 z^{3} + 36 z^{2}

= - \frac{4 z ^{4} - 24 z ^{3} + 36 z ^{2}}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 z ^{4} - 24 z ^{3} + 36 z ^{2}}{9} = - (\frac{4 z ^{4}}{9}) - (- \frac{24 z ^{3}}{9}) - (\frac{36 z ^{2}}{9})

= - (\frac{4 z ^{4}}{9}) - (- \frac{24 z ^{3}}{9}) - (\frac{36 z ^{2}}{9})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{4 z ^{4}}{9} + \frac{24 z ^{3}}{9} - \frac{36 z ^{2}}{9}

Cancel

\frac{24 z ^{3}}{9} : \frac{8 z ^{3}}{3}

= - \frac{4 z ^{4}}{9} + \frac{8 z ^{3}}{3} - \frac{36 z ^{2}}{9}

Divide the numbers:

\frac{36}{9} = 4

= - \frac{4 z ^{4}}{9} + \frac{8 z ^{3}}{3} - 4 z^{2}

\frac{2 ( π - 180 )}{360}

\frac{12 x}{( x ^{2} + 1 ) ^{2}}

(x + 4 y) d x + (4 x - y) d y

\frac{x}{( x + 2 ) ( x ^{2} + 4 )}

e^{2 t} (t - 2)^{2}

What is expand-(z^2(-2z+6)^2)/9 ?
The solution to expand-(z^2(-2z+6)^2)/9 is -(4z^4)/9+(8z^3)/3-4z^2