What is 2(2y^2+2/(y^2)+c) ?

The solution to 2(2y^2+2/(y^2)+c) is (2(2y^4+2+cy^2))/(y^2)

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simplify 2(2y^2+2/(y^2)+c)

simplify

2 (2 y^{2} + \frac{2}{y ^{2}} + c)

\frac{2 ( 2 y ^{4} + 2 + c y ^{2} )}{y ^{2}}

Solution steps

2 (2 y^{2} + \frac{2}{y ^{2}} + c)

Join

2 y^{2} + \frac{2}{y ^{2}} + c : \frac{2 y ^{4} + 2 + c y ^{2}}{y ^{2}}

= 2 \cdot \frac{2 y ^{4} + 2 + c y ^{2}}{y ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 ( 2 y ^{4} + 2 + c y ^{2} )}{y ^{2}}

\frac{( x - 9 y ) ( x - 5 y )}{2 ( x + y )}

(4 x - 5) (6 x + 4)

(\frac{a x}{3} - b y) (\frac{a x}{3} + b y)

f (t - π)

3 (x + Δ x)^{3}

What is 2(2y^2+2/(y^2)+c) ?
The solution to 2(2y^2+2/(y^2)+c) is (2(2y^4+2+cy^2))/(y^2)