What is expand ((x^2-1)^3)/4 ?

The solution to expand ((x^2-1)^3)/4 is (x^6)/4-(3x^4)/4+(3x^2)/4-1/4

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expand ((x^2-1)^3)/4

expand

\frac{( x ^{2} - 1 ) ^{3}}{4}

\frac{x ^{6}}{4} - \frac{3 x ^{4}}{4} + \frac{3 x ^{2}}{4} - \frac{1}{4}

Solution steps

\frac{( x ^{2} - 1 ) ^{3}}{4}

(x^{2} - 1)^{3} = x^{6} - 3 x^{4} + 3 x^{2} - 1

= \frac{x ^{6} - 3 x ^{4} + 3 x ^{2} - 1}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{6} - 3 x ^{4} + 3 x ^{2} - 1}{4} = \frac{x ^{6}}{4} - \frac{3 x ^{4}}{4} + \frac{3 x ^{2}}{4} - \frac{1}{4}

= \frac{x ^{6}}{4} - \frac{3 x ^{4}}{4} + \frac{3 x ^{2}}{4} - \frac{1}{4}

(2 z + 1)^{12}

\frac{- 15 s + 4}{( s ^{2} - 13 s + 26 ) s}

(2 x + y = 9,) (2 x - y = 11)

(x^{4} + 4 x^{3} + 8 x^{2}) \cdot (x - 3 + 5)

lo g_{2} (4 a c)

What is expand ((x^2-1)^3)/4 ?
The solution to expand ((x^2-1)^3)/4 is (x^6)/4-(3x^4)/4+(3x^2)/4-1/4