What is expand (2x+y=9,)(2x-y=11) ?

The solution to expand (2x+y=9,)(2x-y=11) is 4x^2-2xy=11

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expand (2x+y=9,)(2x-y=11)

expand

(2 x + y = 9,) (2 x - y = 11)

4 x^{2} - 2 x y = 11

Solution steps

(2 x + y = 9,) (2 x - y = 11)

= (2 x + 9 =, y) (2 x - 11 = y)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 2 x, b = y = 9,, c = 2 x, d = - y = 11

2 x \cdot 2 x + 2 x (- y = 11) + y = 9, 2 x + y = 9, (- y = 11)

Apply minus-plus rules

+ (- a) = - a

2 \cdot 2 xx - 2 x y = 11 + y = 9, 2 x - y = 9, y = 11

Expand

2 \cdot 2 xx - 2 x y : 4 x^{2} - 2 x y

4 x^{2} - 2 x y = 11

(x^{4} + 4 x^{3} + 8 x^{2}) \cdot (x - 3 + 5)

lo g_{2} (4 a c)

(y + x^{2} + y^{2}) d x - x d y

\frac{( x - 2 ) ( x ^{2} + 2 x + 4 )}{x ^{3}}

(\frac{x ^{4}}{2} + \frac{4}{3 x ^{2}})^{12}

What is expand (2x+y=9,)(2x-y=11) ?
The solution to expand (2x+y=9,)(2x-y=11) is 4x^2-2xy=11