What is expand x^{4/3}(x^{5/3}-x^{7/5}) ?

The solution to expand x^{4/3}(x^{5/3}-x^{7/5}) is x^3-x^{41/15}

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expand x^{4/3}(x^{5/3}-x^{7/5})

expand

x^{\frac{4}{3}} (x^{\frac{5}{3}} - x^{\frac{7}{5}})

x^{3} - x^{\frac{41}{15}}

Solution steps

x^{\frac{4}{3}} (x^{\frac{5}{3}} - x^{\frac{7}{5}})

Apply the distributive law:

a (b - c) = ab - a c

x^{\frac{4}{3}} (x^{\frac{5}{3}} - x^{\frac{7}{5}}) = x^{\frac{4}{3}} x^{\frac{5}{3}} - x^{\frac{4}{3}} x^{\frac{7}{5}}

= x^{\frac{4}{3}} x^{\frac{5}{3}} - x^{\frac{4}{3}} x^{\frac{7}{5}}

x^{\frac{4}{3}} x^{\frac{5}{3}} = x^{3}

x^{\frac{4}{3}} x^{\frac{7}{5}} = x^{\frac{41}{15}}

= x^{3} - x^{\frac{41}{15}}

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What is expand x^{4/3}(x^{5/3}-x^{7/5}) ?
The solution to expand x^{4/3}(x^{5/3}-x^{7/5}) is x^3-x^{41/15}