What is expand ((40-k)(5+k))/(45) ?

The solution to expand ((40-k)(5+k))/(45) is 40/9+(7k)/9-(k^2)/(45)

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expand ((40-k)(5+k))/(45)

expand

\frac{( 40 - k ) ( 5 + k )}{45}

\frac{40}{9} + \frac{7 k}{9} - \frac{k ^{2}}{45}

Solution steps

\frac{( 40 - k ) ( 5 + k )}{45}

Expand

(40 - k) (5 + k) : 200 + 35 k - k^{2}

= \frac{200 + 35 k - k ^{2}}{45}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{200 + 35 k - k ^{2}}{45} = \frac{200}{45} + \frac{35 k}{45} - \frac{k ^{2}}{45}

= \frac{200}{45} + \frac{35 k}{45} - \frac{k ^{2}}{45}

Cancel

\frac{200}{45} : \frac{40}{9}

= \frac{40}{9} + \frac{35 k}{45} - \frac{k ^{2}}{45}

Cancel

\frac{35 k}{45} : \frac{7 k}{9}

= \frac{40}{9} + \frac{7 k}{9} - \frac{k ^{2}}{45}

(10 x^{4} - 11 x^{2} + 1)^{5}

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(2 + x + x^{4}) (5 x - \frac{1}{2 x ^{3}})^{8}

A (- 4, - 5) B (- 2, 3) C (1, - 2)

\frac{( 3 x - 1 ) ^{2}}{9}

What is expand ((40-k)(5+k))/(45) ?
The solution to expand ((40-k)(5+k))/(45) is 40/9+(7k)/9-(k^2)/(45)