What is expand ((1-4x^3)(3+8x^3))/((8x^2-1)(8x^2-3)) ?

The solution to expand ((1-4x^3)(3+8x^3))/((8x^2-1)(8x^2-3)) is (3-4x^3-32x^6)/(64x^4-32x^2+3)

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expand ((1-4x^3)(3+8x^3))/((8x^2-1)(8x^2-3))

expand

\frac{( 1 - 4 x ^{3} ) ( 3 + 8 x ^{3} )}{( 8 x ^{2} - 1 ) ( 8 x ^{2} - 3 )}

\frac{3 - 4 x ^{3} - 32 x ^{6}}{64 x ^{4} - 32 x ^{2} + 3}

Solution steps

\frac{( 1 - 4 x ^{3} ) ( 3 + 8 x ^{3} )}{( 8 x ^{2} - 1 ) ( 8 x ^{2} - 3 )}

Expand

(8 x^{2} - 1) (8 x^{2} - 3) : 64 x^{4} - 32 x^{2} + 3

= \frac{( - 4 x ^{3} + 1 ) ( 8 x ^{3} + 3 )}{64 x ^{4} - 32 x ^{2} + 3}

Expand

(1 - 4 x^{3}) (3 + 8 x^{3}) : 3 - 4 x^{3} - 32 x^{6}

= \frac{3 - 4 x ^{3} - 32 x ^{6}}{64 x ^{4} - 32 x ^{2} + 3}

(x - 1 + 6) (x - 1 - 6) (x + 2 - 42)

\frac{4}{( x + 2 ) ^{3}}

\frac{2 ^{- x - 1} ( x + 2 )}{x ( x + 1 )}

150 [4 (0.005) + \frac{1}{2} sin ((8) 0.005)]

- 4 (x - 2) e^{8 x}

What is expand ((1-4x^3)(3+8x^3))/((8x^2-1)(8x^2-3)) ?
The solution to expand ((1-4x^3)(3+8x^3))/((8x^2-1)(8x^2-3)) is (3-4x^3-32x^6)/(64x^4-32x^2+3)