What is ((3x^2)/4-2xy^3)((3x^2)/4+2xy^3) ?

The solution to ((3x^2)/4-2xy^3)((3x^2)/4+2xy^3) is ((-8xy^3+3x^2)(8xy^3+3x^2))/(16)

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simplify ((3x^2)/4-2xy^3)((3x^2)/4+2xy^3)

simplify

(\frac{3 x ^{2}}{4} - 2 x y^{3}) (\frac{3 x ^{2}}{4} + 2 x y^{3})

\frac{( - 8 x y ^{3} + 3 x ^{2} ) ( 8 x y ^{3} + 3 x ^{2} )}{16}

Solution steps

(\frac{3 x ^{2}}{4} - 2 x y^{3}) (\frac{3 x ^{2}}{4} + 2 x y^{3})

Join

\frac{3 x ^{2}}{4} - 2 x y^{3} : \frac{- 8 x y ^{3} + 3 x ^{2}}{4}

= \frac{- 8 x y ^{3} + 3 x ^{2}}{4} (\frac{3 x ^{2}}{4} + 2 x y^{3})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( - 8 x y ^{3} + 3 x ^{2} ) ( \frac{3 x ^{2}}{4} + 2 x y ^{3} )}{4}

Simplify

(- 8 x y^{3} + 3 x^{2}) (\frac{3 x ^{2}}{4} + 2 x y^{3}) : \frac{( - 8 x y ^{3} + 3 x ^{2} ) ( 8 x y ^{3} + 3 x ^{2} )}{4}

= \frac{\frac{( - 8 x y ^{3} + 3 x ^{2} ) ( 8 x y ^{3} + 3 x ^{2} )}{4}}{4}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( - 8 x y ^{3} + 3 x ^{2} ) ( 8 x y ^{3} + 3 x ^{2} )}{4 \cdot 4}

Multiply the numbers:

4 \cdot 4 = 16

= \frac{( - 8 x y ^{3} + 3 x ^{2} ) ( 8 x y ^{3} + 3 x ^{2} )}{16}

\frac{7 x ( x + 1 )}{( x + 3 ) ( x - 3 )}

8 (2 x ln (x) + x)

x (\frac{100}{x - 8} + 5)

\frac{( x ^{6} + 4 ) ^{2}}{16 x ^{6}}

(sec^{3} (y)) (2 x sin (y) - cos^{3} (y))

What is ((3x^2)/4-2xy^3)((3x^2)/4+2xy^3) ?
The solution to ((3x^2)/4-2xy^3)((3x^2)/4+2xy^3) is ((-8xy^3+3x^2)(8xy^3+3x^2))/(16)