What is expand ((2x-1)^2)/(x+3) ?

The solution to expand ((2x-1)^2)/(x+3) is (4x^2-4x+1)/(x+3)

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expand ((2x-1)^2)/(x+3)

expand

\frac{( 2 x - 1 ) ^{2}}{x + 3}

\frac{4 x ^{2} - 4 x + 1}{x + 3}

Solution steps

\frac{( 2 x - 1 ) ^{2}}{x + 3}

(2 x - 1)^{2} = 4 x^{2} - 4 x + 1

= \frac{4 x ^{2} - 4 x + 1}{x + 3}

(x - 3) (x + 1 - 5) (x + 1 + 5)

\frac{5}{x ^{3} - 2} (- 2, - \frac{1}{2})

\frac{x - 3}{x ^{2} ( x ^{2} + 3 )}

(12 J e^{36 J β} + 6 J e^{12 J β})^{2}

\frac{- 8 x + 4}{( x ^{2} + x - 6 ) ^{2}}

What is expand ((2x-1)^2)/(x+3) ?
The solution to expand ((2x-1)^2)/(x+3) is (4x^2-4x+1)/(x+3)