What is expand 5/(x^3-2)(-2,-1/2) ?

The solution to expand 5/(x^3-2)(-2,-1/2) is -2*5/(x^3-2),-1/2*5/(x^3-2)

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expand 5/(x^3-2)(-2,-1/2)

expand

\frac{5}{x ^{3} - 2} (- 2, - \frac{1}{2})

- 2 \cdot \frac{5}{x ^{3} - 2}, - \frac{1}{2} \cdot \frac{5}{x ^{3} - 2}

Solution steps

\frac{5}{x ^{3} - 2} (- 2, - \frac{1}{2})

= (- 2, - \frac{1}{2}) \frac{5}{x ^{3} - 2}

Apply the distributive law:

a (b - c) = ab - a c

a = \frac{5}{x ^{3} - 2}, b = - 2,, c = \frac{1}{2}

= \frac{5}{x ^{3} - 2} (- 2,) - \frac{5}{x ^{3} - 2} \cdot \frac{1}{2}

Apply minus-plus rules

+ (- a) = - a

= - 2 \cdot \frac{5}{x ^{3} - 2}, - \frac{1}{2} \cdot \frac{5}{x ^{3} - 2}

\frac{x - 3}{x ^{2} ( x ^{2} + 3 )}

(12 J e^{36 J β} + 6 J e^{12 J β})^{2}

\frac{- 8 x + 4}{( x ^{2} + x - 6 ) ^{2}}

(3 x - \frac{x ^{2}}{3})^{13}

- i ((1 + i)^{n} - 1)

What is expand 5/(x^3-2)(-2,-1/2) ?
The solution to expand 5/(x^3-2)(-2,-1/2) is -2*5/(x^3-2),-1/2*5/(x^3-2)