What is simplify-i((1+i)^n-1) ?

The solution to simplify-i((1+i)^n-1) is -i(1+i)^n+i

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simplify-i((1+i)^n-1)

simplify

- i ((1 + i)^{n} - 1)

- i (1 + i)^{n} + i

Solution steps

- i ((1 + i)^{n} - 1)

Apply the distributive law:

a (b - c) = ab - a c

- i ((1 + i)^{n} - 1) = - i (1 + i)^{n} - (- i) \cdot 1

= - i (1 + i)^{n} - (- i) \cdot 1

Simplify

- (- i) \cdot 1 : i

= - i (1 + i)^{n} + i

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What is simplify-i((1+i)^n-1) ?
The solution to simplify-i((1+i)^n-1) is -i(1+i)^n+i