What is expand (e^{2x}-5)sech(x^2+7x-1) ?

The solution to expand (e^{2x}-5)sech(x^2+7x-1) is e^{2x}sech(x^2+7x-1)-5sech(x^2+7x-1)

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expand (e^{2x}-5)sech(x^2+7x-1)

expand

(e^{2 x} - 5) sech (x^{2} + 7 x - 1)

e^{2 x} sech (x^{2} + 7 x - 1) - 5 sech (x^{2} + 7 x - 1)

Solution steps

(e^{2 x} - 5) sech (x^{2} + 7 x - 1)

= sech (x^{2} + 7 x - 1) (e^{2 x} - 5)

Apply the distributive law:

a (b - c) = ab - a c

a = sech (x^{2} + 7 x - 1), b = e^{2 x}, c = 5

= sech (x^{2} + 7 x - 1) e^{2 x} - sech (x^{2} + 7 x - 1) \cdot 5

= e^{2 x} sech (x^{2} + 7 x - 1) - 5 sech (x^{2} + 7 x - 1)

l {(3 e^{- 3 t} - 2 t)^{2} + (cos (3 t) - e^{5 t})^{2}}

\frac{( 2 x - 3 ) ( 1 - x ^{2} )}{( x ^{2} + 1 ) ( 5 - x )}

(- 3 + i 3)^{14}

(\frac{4}{16} x + \frac{5}{16} y + \frac{3}{16} z + \frac{4}{16} q)^{4}

\frac{p + 2}{( p + 1 ) ( p - 2 ) ( p ^{2} + 4 )}

What is expand (e^{2x}-5)sech(x^2+7x-1) ?
The solution to expand (e^{2x}-5)sech(x^2+7x-1) is e^{2x}sech(x^2+7x-1)-5sech(x^2+7x-1)