What is expand 3x^{1/3}(x+2) ?

The solution to expand 3x^{1/3}(x+2) is 3x^{4/3}+6x^{1/3}

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expand 3x^{1/3}(x+2)

expand

3 x^{\frac{1}{3}} (x + 2)

3 x^{\frac{4}{3}} + 6 x^{\frac{1}{3}}

Solution steps

3 x^{\frac{1}{3}} (x + 2)

Apply the distributive law:

a (b + c) = ab + a c

3 x^{\frac{1}{3}} (x + 2) = 3 x^{\frac{1}{3}} x + 3 x^{\frac{1}{3}} \cdot 2

= 3 x^{\frac{1}{3}} x + 3 x^{\frac{1}{3}} \cdot 2

3 x^{\frac{1}{3}} x = 3 x^{\frac{4}{3}}

3 x^{\frac{1}{3}} \cdot 2 = 6 x^{\frac{1}{3}}

= 3 x^{\frac{4}{3}} + 6 x^{\frac{1}{3}}

x (3 + 5 x)

\frac{d}{d y} ((x) (x^{y} + \frac{1}{x ^{2}}))

(4 e - 2 x)^{3}

(2 x - 5) (3 x^{2} + 4 x) d x

\frac{x ^{2} + 2 x - 1}{( x ^{2} - x - 2 ) ^{2}}

What is expand 3x^{1/3}(x+2) ?
The solution to expand 3x^{1/3}(x+2) is 3x^{4/3}+6x^{1/3}