What is 3(log_{4}(x)+1) ?

The solution to 3(log_{4}(x)+1) is 3log_{4}(x)+3

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simplify 3(log_{4}(x)+1)

simplify

3 (lo g_{4} (x) + 1)

3 lo g_{4} (x) + 3

Solution steps

3 (lo g_{4} (x) + 1)

Apply the distributive law:

a (b + c) = ab + a c

3 (lo g_{4} (x) + 1) = 3 lo g_{4} (x) + 3 \cdot 1

= 3 lo g_{4} (x) + 3 \cdot 1

Multiply the numbers:

3 \cdot 1 = 3

= 3 lo g_{4} (x) + 3

\frac{k ^{7} + 3}{2 k ^{4}}

(1 + 21 t)^{2} + (1 + 21 t)^{2}

A (5, - 6) B (- 7, 2)

\frac{d}{d t} ((x) (t^{3} - t^{2}))

- 36 (x - \frac{1}{4}) (x - 1)