What is expand pi(x-2)^2*(3x-4) ?

The solution to expand pi(x-2)^2*(3x-4) is 3pix^3-16pix^2+28pix-16pi

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expand pi(x-2)^2*(3x-4)

expand

π (x - 2)^{2} \cdot (3 x - 4)

3 π x^{3} - 16 π x^{2} + 28 π x - 16 π

Solution steps

π (x - 2)^{2} (3 x - 4)

Apply the distributive law:

a (b - c) = ab - a c

a = π (x - 2)^{2}, b = 3 x, c = 4

= π (x - 2)^{2} \cdot 3 x - π (x - 2)^{2} \cdot 4

= 3 π x (x - 2)^{2} - 4 π (x - 2)^{2}

Simplify

3 π x (x - 2)^{2} - 4 π (x - 2)^{2} : 3 π x^{3} - 16 π x^{2} + 28 π x - 16 π

= 3 π x^{3} - 16 π x^{2} + 28 π x - 16 π

(2 x - y = H (x, y)) d H (x, y)

\frac{( 16 - x ) ^{2} x}{32}

(1 + cos (x))^{4} \cdot sin (x)

\frac{1}{10} (e^{x} - e^{- x})

x^{3} δ (x - 2)

What is expand pi(x-2)^2*(3x-4) ?
The solution to expand pi(x-2)^2*(3x-4) is 3pix^3-16pix^2+28pix-16pi