What is (x-1)(x^2-9)(x^2-x+1/2)(x^2+4) ?

The solution to (x-1)(x^2-9)(x^2-x+1/2)(x^2+4) is ((x-1)(x^2-9)(2x^2-2x+1)(x^2+4))/2

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simplify (x-1)(x^2-9)(x^2-x+1/2)(x^2+4)

simplify

(x - 1) (x^{2} - 9) (x^{2} - x + \frac{1}{2}) (x^{2} + 4)

\frac{( x - 1 ) ( x ^{2} - 9 ) ( 2 x ^{2} - 2 x + 1 ) ( x ^{2} + 4 )}{2}

Solution steps

(x - 1) (x^{2} - 9) (x^{2} - x + \frac{1}{2}) (x^{2} + 4)

Simplify

x^{2} - x + \frac{1}{2} : \frac{2 x ^{2} - 2 x + 1}{2}

= (x - 1) (x^{2} - 9) \frac{2 x ^{2} - 2 x + 1}{2} (x^{2} + 4)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x - 1 ) ( x ^{2} - 9 ) ( 2 x ^{2} - 2 x + 1 ) ( x ^{2} + 4 )}{2}

- sin (θ) (1 - x^{2})

x (2 - x^{2})

\frac{d}{d ^{4}} (y = 2 x^{4} - 6 x^{3} + 7 x^{2} + 5 x)

(y - 2) + (x + 7) y^{'} (x)

(1 - t) \cdot (0, 1, 0)

What is (x-1)(x^2-9)(x^2-x+1/2)(x^2+4) ?
The solution to (x-1)(x^2-9)(x^2-x+1/2)(x^2+4) is ((x-1)(x^2-9)(2x^2-2x+1)(x^2+4))/2