What are the solutions to the equation x^2+20x+72=3x ?

The solutions to the equation x^2+20x+72=3x are x=-8,x=-9

Find the zeros of x^2+20x+72=3x

The zeros of x^2+20x+72=3x are x=-8,x=-9

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x^{2} + 20 x + 72 = 3 x

x = - 8, x = - 9

Solution steps

x^{2} + 20 x + 72 = 3 x

Move

3 x

to the left side

x^{2} + 17 x + 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 1 \cdot 72}{2 \cdot 1}

1 7^{2} - 4 \cdot 1 \cdot 72 = 1

x_{1, 2} = \frac{- 17 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 17 + 1}{2 \cdot 1}, x_{2} = \frac{- 17 - 1}{2 \cdot 1}

x = \frac{- 17 + 1}{2 \cdot 1} : - 8

x = \frac{- 17 - 1}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = - 8, x = - 9

∣ 2 x ∣ = 5

x^{3} - 5 x^{2} - 5 x + 25

(1 + i)^{10}

0 y - 2 = 19 - 4 y + 1 y

16 q^{2} + 56 q + 49

What are the solutions to the equation x^2+20x+72=3x ?
The solutions to the equation x^2+20x+72=3x are x=-8,x=-9
Find the zeros of x^2+20x+72=3x
The zeros of x^2+20x+72=3x are x=-8,x=-9