What is expand (2x^3-x+4)/(x+1)+sqrt(x^2) ?

The solution to expand (2x^3-x+4)/(x+1)+sqrt(x^2) is (2x^3+x^2+4)/(x+1)

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expand (2x^3-x+4)/(x+1)+sqrt(x^2)

expand

\frac{2 x ^{3} - x + 4}{x + 1} + x^{2}

\frac{2 x ^{3} + x ^{2} + 4}{x + 1}

Solution steps

\frac{2 x ^{3} - x + 4}{x + 1} + x^{2}

Apply radical rule:

assuming

a \geq 0

= \frac{2 x ^{3} - x + 4}{x + 1} + x

Convert element to fraction:

x = \frac{x ( x + 1 )}{x + 1}

= \frac{2 x ^{3} - x + 4}{x + 1} + \frac{x ( x + 1 )}{x + 1}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 x ^{3} - x + 4 + x ( x + 1 )}{x + 1}

Expand

2 x^{3} - x + 4 + x (x + 1) : 2 x^{3} + x^{2} + 4

= \frac{2 x ^{3} + x ^{2} + 4}{x + 1}

(1 + b e) (1 + a d)

(2 π + j w) (- j w - 2 π)

\frac{( 5 - 2 m ^{5} ) ^{2}}{25}

x^{2} (x^{3} + 5 x^{2} - 3 x + 3)

lo g_{\frac{x ( x + 4 )}{( x + 2 ) ^{4}}} (x)

What is expand (2x^3-x+4)/(x+1)+sqrt(x^2) ?
The solution to expand (2x^3-x+4)/(x+1)+sqrt(x^2) is (2x^3+x^2+4)/(x+1)