What is expand (2pi+jw)(-jw-2pi) ?

The solution to expand (2pi+jw)(-jw-2pi) is -4pijw-j^2w^2-4pi^2

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expand (2pi+jw)(-jw-2pi)

expand

(2 π + j w) (- j w - 2 π)

- 4 πj w - j^{2} w^{2} - 4 π^{2}

Solution steps

(2 π + j w) (- j w - 2 π)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 2 π, b = j w, c = - j w, d = - 2 π

= 2 π (- j w) + 2 π (- 2 π) + j w (- j w) + j w (- 2 π)

Apply minus-plus rules

+ (- a) = - a

= - 2 πj w - 2 \cdot 2 ππ - jj ww - 2 πj w

Simplify

- 2 πj w - 2 \cdot 2 ππ - jj ww - 2 πj w : - 4 πj w - j^{2} w^{2} - 4 π^{2}

= - 4 πj w - j^{2} w^{2} - 4 π^{2}

\frac{( 5 - 2 m ^{5} ) ^{2}}{25}

x^{2} (x^{3} + 5 x^{2} - 3 x + 3)

lo g_{\frac{x ( x + 4 )}{( x + 2 ) ^{4}}} (x)

\frac{( x + 3 ) ( x + 6 ) ^{2} ( x + 1 )}{( x - 3 ) ( x + 4 )}

0.0759 \cdot 2. 1^{5} \cdot (1 - (0, 5)^{2})

What is expand (2pi+jw)(-jw-2pi) ?
The solution to expand (2pi+jw)(-jw-2pi) is -4pijw-j^2w^2-4pi^2